Base | Representation |
---|---|
bin | 110000011100110011101110… |
… | …000101101000011110000011 |
3 | 1000221110210222120121111002022 |
4 | 300130303232011220132003 |
5 | 210412144421424134133 |
6 | 2033110152213112055 |
7 | 62611643353465316 |
oct | 6034635605503603 |
9 | 1027423876544068 |
10 | 213085911943043 |
11 | 61994256176467 |
12 | 1ba9558892862b |
13 | 91b8bb8b26449 |
14 | 3a895ada3097d |
15 | 1997cc0c36998 |
hex | c1ccee168783 |
213085911943043 has 2 divisors, whose sum is σ = 213085911943044. Its totient is φ = 213085911943042.
The previous prime is 213085911942931. The next prime is 213085911943117. The reversal of 213085911943043 is 340349119580312.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 213085911943043 - 212 = 213085911938947 is a prime.
It is not a weakly prime, because it can be changed into another prime (213085911943843) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106542955971521 + 106542955971522.
It is an arithmetic number, because the mean of its divisors is an integer number (106542955971522).
Almost surely, 2213085911943043 is an apocalyptic number.
213085911943043 is a deficient number, since it is larger than the sum of its proper divisors (1).
213085911943043 is an equidigital number, since it uses as much as digits as its factorization.
213085911943043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2799360, while the sum is 53.
The spelling of 213085911943043 in words is "two hundred thirteen trillion, eighty-five billion, nine hundred eleven million, nine hundred forty-three thousand, forty-three".
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