Base | Representation |
---|---|
bin | 11111000000101001101… |
… | …011110001110101100111 |
3 | 21112201111021022220220111 |
4 | 133000221223301311213 |
5 | 234403243244332444 |
6 | 4310545212313451 |
7 | 306650146442314 |
oct | 37005153616547 |
9 | 7481437286814 |
10 | 2131003120999 |
11 | 751831785635 |
12 | 2a5004772887 |
13 | 125c501c980c |
14 | 751d9279d0b |
15 | 3a673e3c234 |
hex | 1f029af1d67 |
2131003120999 has 2 divisors, whose sum is σ = 2131003121000. Its totient is φ = 2131003120998.
The previous prime is 2131003120979. The next prime is 2131003121069. The reversal of 2131003120999 is 9990213001312.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2131003120999 - 231 = 2128855637351 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2131003120979) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065501560499 + 1065501560500.
It is an arithmetic number, because the mean of its divisors is an integer number (1065501560500).
Almost surely, 22131003120999 is an apocalyptic number.
2131003120999 is a deficient number, since it is larger than the sum of its proper divisors (1).
2131003120999 is an equidigital number, since it uses as much as digits as its factorization.
2131003120999 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 26244, while the sum is 40.
The spelling of 2131003120999 in words is "two trillion, one hundred thirty-one billion, three million, one hundred twenty thousand, nine hundred ninety-nine".
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