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213102311300 = 22522131023113
BaseRepresentation
bin1100011001110111100…
…0110011011110000100
3202101001110121001200022
43012131320303132010
511442413142430200
6241521534034312
721252605521214
oct3063570633604
9671043531608
10213102311300
118241577664a
1235373648998
13171319636b8
14a458280244
155823885885
hex319de33784

213102311300 has 18 divisors (see below), whose sum is σ = 462432015738. Its totient is φ = 85240924480.

The previous prime is 213102311297. The next prime is 213102311311. The reversal of 213102311300 is 3113201312.

It can be written as a sum of positive squares in 3 ways, for example, as 984955456 + 212117355844 = 31384^2 + 460562^2 .

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1065511457 + ... + 1065511656.

It is an arithmetic number, because the mean of its divisors is an integer number (25690667541).

Almost surely, 2213102311300 is an apocalyptic number.

213102311300 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

213102311300 is an abundant number, since it is smaller than the sum of its proper divisors (249329704438).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

213102311300 is a wasteful number, since it uses less digits than its factorization.

213102311300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2131023127 (or 2131023120 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 213102311300 its reverse (3113201312), we get a palindrome (216215512612).

The spelling of 213102311300 in words is "two hundred thirteen billion, one hundred two million, three hundred eleven thousand, three hundred".

Divisors: 1 2 4 5 10 20 25 50 100 2131023113 4262046226 8524092452 10655115565 21310231130 42620462260 53275577825 106551155650 213102311300