Base | Representation |
---|---|
bin | 11111000000101011011… |
… | …001111111001010011011 |
3 | 21112201120021200201010001 |
4 | 133000223121333022123 |
5 | 234403323143331134 |
6 | 4310552123433431 |
7 | 306650650140043 |
oct | 37005331771233 |
9 | 7481507621101 |
10 | 2131032011419 |
11 | 751847018413 |
12 | 2a5012385877 |
13 | 125c561a373c |
14 | 751dd03a723 |
15 | 3a676747414 |
hex | 1f02b67f29b |
2131032011419 has 2 divisors, whose sum is σ = 2131032011420. Its totient is φ = 2131032011418.
The previous prime is 2131032011387. The next prime is 2131032011447. The reversal of 2131032011419 is 9141102301312.
It is an a-pointer prime, because the next prime (2131032011447) can be obtained adding 2131032011419 to its sum of digits (28).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2131032011419 - 25 = 2131032011387 is a prime.
It is a super-2 number, since 2×21310320114192 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2131032011489) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065516005709 + 1065516005710.
It is an arithmetic number, because the mean of its divisors is an integer number (1065516005710).
Almost surely, 22131032011419 is an apocalyptic number.
2131032011419 is a deficient number, since it is larger than the sum of its proper divisors (1).
2131032011419 is an equidigital number, since it uses as much as digits as its factorization.
2131032011419 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 28.
The spelling of 2131032011419 in words is "two trillion, one hundred thirty-one billion, thirty-two million, eleven thousand, four hundred nineteen".
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