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2131043303 is a prime number
BaseRepresentation
bin111111100000101…
…0010001111100111
312111111221012211202
41333001102033213
513331021341203
6551243353115
7103544366144
oct17701221747
95444835752
102131043303
119a3a11414
124b582279b
1327c66998c
1416304b3cb
15c714a388
hex7f0523e7

2131043303 has 2 divisors, whose sum is σ = 2131043304. Its totient is φ = 2131043302.

The previous prime is 2131043297. The next prime is 2131043329. The reversal of 2131043303 is 3033401312.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2131043303 - 210 = 2131042279 is a prime.

It is a super-2 number, since 2×21310433032 = 9082691118522299618, which contains 22 as substring.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2131043353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065521651 + 1065521652.

It is an arithmetic number, because the mean of its divisors is an integer number (1065521652).

Almost surely, 22131043303 is an apocalyptic number.

2131043303 is a deficient number, since it is larger than the sum of its proper divisors (1).

2131043303 is an equidigital number, since it uses as much as digits as its factorization.

2131043303 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 20.

The square root of 2131043303 is about 46163.2245732466. The cubic root of 2131043303 is about 1286.8583895610.

Adding to 2131043303 its reverse (3033401312), we get a palindrome (5164444615).

The spelling of 2131043303 in words is "two billion, one hundred thirty-one million, forty-three thousand, three hundred three".