Base | Representation |
---|---|
bin | 110000011101001010100001… |
… | …101101010110110000010011 |
3 | 1000221120011012012210122022202 |
4 | 300131022201231112300103 |
5 | 210413100044440030022 |
6 | 2033125322155553415 |
7 | 62613501246301052 |
oct | 6035124155266023 |
9 | 1027504165718282 |
10 | 213110400314387 |
11 | 619a3682223294 |
12 | 1ba9a281a5b86b |
13 | 91bb2bc3658c4 |
14 | 3a8a854076399 |
15 | 1998755a45592 |
hex | c1d2a1b56c13 |
213110400314387 has 2 divisors, whose sum is σ = 213110400314388. Its totient is φ = 213110400314386.
The previous prime is 213110400314359. The next prime is 213110400314417. The reversal of 213110400314387 is 783413004011312.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 213110400314387 - 28 = 213110400314131 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 213110400314387.
It is not a weakly prime, because it can be changed into another prime (213110400314687) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106555200157193 + 106555200157194.
It is an arithmetic number, because the mean of its divisors is an integer number (106555200157194).
Almost surely, 2213110400314387 is an apocalyptic number.
213110400314387 is a deficient number, since it is larger than the sum of its proper divisors (1).
213110400314387 is an equidigital number, since it uses as much as digits as its factorization.
213110400314387 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48384, while the sum is 38.
Adding to 213110400314387 its reverse (783413004011312), we get a palindrome (996523404325699).
The spelling of 213110400314387 in words is "two hundred thirteen trillion, one hundred ten billion, four hundred million, three hundred fourteen thousand, three hundred eighty-seven".
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