Base | Representation |
---|---|
bin | 11111000000110000000… |
… | …100010101000101000111 |
3 | 21112201202201212010020222 |
4 | 133000300010111011013 |
5 | 234404003204020403 |
6 | 4311004000014555 |
7 | 306652616662514 |
oct | 37006004250507 |
9 | 7481681763228 |
10 | 2131110220103 |
11 | 751887185797 |
12 | 2a503460145b |
13 | 125c69457677 |
14 | 7520959830b |
15 | 3a67d545338 |
hex | 1f030115147 |
2131110220103 has 2 divisors, whose sum is σ = 2131110220104. Its totient is φ = 2131110220102.
The previous prime is 2131110220049. The next prime is 2131110220133. The reversal of 2131110220103 is 3010220111312.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2131110220103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2131110220133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065555110051 + 1065555110052.
It is an arithmetic number, because the mean of its divisors is an integer number (1065555110052).
Almost surely, 22131110220103 is an apocalyptic number.
2131110220103 is a deficient number, since it is larger than the sum of its proper divisors (1).
2131110220103 is an equidigital number, since it uses as much as digits as its factorization.
2131110220103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 2131110220103 its reverse (3010220111312), we get a palindrome (5141330331415).
The spelling of 2131110220103 in words is "two trillion, one hundred thirty-one billion, one hundred ten million, two hundred twenty thousand, one hundred three".
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