Base | Representation |
---|---|
bin | 1100011001111001101… |
… | …1001111110001100101 |
3 | 202101002002120202220112 |
4 | 3012132123033301211 |
5 | 11442423000341013 |
6 | 241522455342405 |
7 | 21253045334306 |
oct | 3063633176145 |
9 | 671062522815 |
10 | 213111340133 |
11 | 8241a88309a |
12 | 35376681a05 |
13 | 171337a51c3 |
14 | a4595507ad |
15 | 582456aba8 |
hex | 319e6cfc65 |
213111340133 has 2 divisors, whose sum is σ = 213111340134. Its totient is φ = 213111340132.
The previous prime is 213111340121. The next prime is 213111340153. The reversal of 213111340133 is 331043111312.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 174989949124 + 38121391009 = 418318^2 + 195247^2 .
It is a cyclic number.
It is not a de Polignac number, because 213111340133 - 210 = 213111339109 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 213111340099 and 213111340108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (213111340153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106555670066 + 106555670067.
It is an arithmetic number, because the mean of its divisors is an integer number (106555670067).
Almost surely, 2213111340133 is an apocalyptic number.
It is an amenable number.
213111340133 is a deficient number, since it is larger than the sum of its proper divisors (1).
213111340133 is an equidigital number, since it uses as much as digits as its factorization.
213111340133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 213111340133 its reverse (331043111312), we get a palindrome (544154451445).
The spelling of 213111340133 in words is "two hundred thirteen billion, one hundred eleven million, three hundred forty thousand, one hundred thirty-three".
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