Base | Representation |
---|---|
bin | 11111000000110000110… |
… | …110010110100000011011 |
3 | 21112201210122112022222021 |
4 | 133000300312112200123 |
5 | 234404020033130042 |
6 | 4311005145035311 |
7 | 306653136306124 |
oct | 37006066264033 |
9 | 7481718468867 |
10 | 2131123333147 |
11 | 751893621816 |
12 | 2a5038a85b37 |
13 | 125c6c099173 |
14 | 7520b20d04b |
15 | 3a67e785867 |
hex | 1f030d9681b |
2131123333147 has 2 divisors, whose sum is σ = 2131123333148. Its totient is φ = 2131123333146.
The previous prime is 2131123333109. The next prime is 2131123333159. The reversal of 2131123333147 is 7413333211312.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2131123333147 - 215 = 2131123300379 is a prime.
It is a super-2 number, since 2×21311233331472 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2131123331147) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065561666573 + 1065561666574.
It is an arithmetic number, because the mean of its divisors is an integer number (1065561666574).
Almost surely, 22131123333147 is an apocalyptic number.
2131123333147 is a deficient number, since it is larger than the sum of its proper divisors (1).
2131123333147 is an equidigital number, since it uses as much as digits as its factorization.
2131123333147 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 27216, while the sum is 34.
Adding to 2131123333147 its reverse (7413333211312), we get a palindrome (9544456544459).
The spelling of 2131123333147 in words is "two trillion, one hundred thirty-one billion, one hundred twenty-three million, three hundred thirty-three thousand, one hundred forty-seven".
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