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213113030129 is a prime number
BaseRepresentation
bin1100011001111010000…
…1101100010111110001
3202101002012202122010222
43012132201230113301
511442423413431004
6241522555502425
721253065603356
oct3063641542761
9671065678128
10213113030129
118242082788a
1235377157a15
1317133c474bc
14a45987062d
1558247a17be
hex319e86c5f1

213113030129 has 2 divisors, whose sum is σ = 213113030130. Its totient is φ = 213113030128.

The previous prime is 213113030087. The next prime is 213113030153. The reversal of 213113030129 is 921030311312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 198268044529 + 14844985600 = 445273^2 + 121840^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-213113030129 is a prime.

It is a super-2 number, since 2×2131130301292 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 213113030098 and 213113030107.

It is not a weakly prime, because it can be changed into another prime (213113030159) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106556515064 + 106556515065.

It is an arithmetic number, because the mean of its divisors is an integer number (106556515065).

Almost surely, 2213113030129 is an apocalyptic number.

It is an amenable number.

213113030129 is a deficient number, since it is larger than the sum of its proper divisors (1).

213113030129 is an equidigital number, since it uses as much as digits as its factorization.

213113030129 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972, while the sum is 26.

The spelling of 213113030129 in words is "two hundred thirteen billion, one hundred thirteen million, thirty thousand, one hundred twenty-nine".