Base | Representation |
---|---|
bin | 11111000000110001011… |
… | …100011000000100110011 |
3 | 21112201211100021202100121 |
4 | 133000301130120010303 |
5 | 234404030111113133 |
6 | 4311010142431111 |
7 | 306653320113055 |
oct | 37006134300463 |
9 | 7481740252317 |
10 | 2131133301043 |
11 | 75189920a84a |
12 | 2a5040292497 |
13 | 125c71179226 |
14 | 7520c6858d5 |
15 | 3a6805a402d |
hex | 1f031718133 |
2131133301043 has 2 divisors, whose sum is σ = 2131133301044. Its totient is φ = 2131133301042.
The previous prime is 2131133301029. The next prime is 2131133301109. The reversal of 2131133301043 is 3401033311312.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2131133301043 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2131133300999 and 2131133301017.
It is not a weakly prime, because it can be changed into another prime (2131133301023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065566650521 + 1065566650522.
It is an arithmetic number, because the mean of its divisors is an integer number (1065566650522).
Almost surely, 22131133301043 is an apocalyptic number.
2131133301043 is a deficient number, since it is larger than the sum of its proper divisors (1).
2131133301043 is an equidigital number, since it uses as much as digits as its factorization.
2131133301043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 2131133301043 its reverse (3401033311312), we get a palindrome (5532166612355).
The spelling of 2131133301043 in words is "two trillion, one hundred thirty-one billion, one hundred thirty-three million, three hundred one thousand, forty-three".
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