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21311412421231 is a prime number
BaseRepresentation
bin1001101100001111100110…
…01010101100001001101111
32210110100110222022000200201
410312013303022230021233
510243131233034434411
6113154154441334331
74326461444463352
oct466076312541157
983410428260621
1021311412421231
1168771347a7209
122482364a973a7
13bb78718a5a3a
14539699392299
1526e55ab643c1
hex1361f32ac26f

21311412421231 has 2 divisors, whose sum is σ = 21311412421232. Its totient is φ = 21311412421230.

The previous prime is 21311412421207. The next prime is 21311412421237. The reversal of 21311412421231 is 13212421411312.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 21311412421231 - 25 = 21311412421199 is a prime.

It is a super-2 number, since 2×213114124212312 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 21311412421231.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21311412421237) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10655706210615 + 10655706210616.

It is an arithmetic number, because the mean of its divisors is an integer number (10655706210616).

Almost surely, 221311412421231 is an apocalyptic number.

21311412421231 is a deficient number, since it is larger than the sum of its proper divisors (1).

21311412421231 is an equidigital number, since it uses as much as digits as its factorization.

21311412421231 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2304, while the sum is 28.

Adding to 21311412421231 its reverse (13212421411312), we get a palindrome (34523833832543).

The spelling of 21311412421231 in words is "twenty-one trillion, three hundred eleven billion, four hundred twelve million, four hundred twenty-one thousand, two hundred thirty-one".