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213120113130000 = 243254531012771597
BaseRepresentation
bin110000011101010011100100…
…101000110011101000010000
31000221121002021010011210112100
4300131103210220303220100
5210413224442430130000
62033134010043200400
762614264036000536
oct6035234450635020
91027532233153470
10213120113130000
11619a780691742a
121baa0132816100
1391bc1a96c158b
143a8b0d6000156
151998b235c6a00
hexc1d4e4a33a10

213120113130000 has 1200 divisors, whose sum is σ = 770143372620336. Its totient is φ = 54973900800000.

The previous prime is 213120113129953. The next prime is 213120113130007. The reversal of 213120113130000 is 31311021312.

213120113130000 is a `hidden beast` number, since 2 + 1 + 31 + 201 + 131 + 300 + 0 + 0 = 666.

It can be written as a sum of positive squares in 40 ways, for example, as 203366309550336 + 9753803579664 = 14260656^2 + 3123108^2 .

It is a tau number, because it is divible by the number of its divisors (1200).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is not an unprimeable number, because it can be changed into a prime (213120113130007) by changing a digit.

It is a polite number, since it can be written in 239 ways as a sum of consecutive naturals, for example, 133450289202 + ... + 133450290798.

Almost surely, 2213120113130000 is an apocalyptic number.

213120113130000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 213120113130000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (385071686310168).

213120113130000 is an abundant number, since it is smaller than the sum of its proper divisors (557023259490336).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

213120113130000 is a wasteful number, since it uses less digits than its factorization.

213120113130000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2062 (or 2038 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 213120113130000 its reverse (31311021312), we get a palindrome (213151424151312).

The spelling of 213120113130000 in words is "two hundred thirteen trillion, one hundred twenty billion, one hundred thirteen million, one hundred thirty thousand".