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213120231000000 = 26356234765717
BaseRepresentation
bin110000011101010011101011…
…101010011100011111000000
31000221121002120022222012202220
4300131103223222130133000
5210413230213114000000
62033134025453411040
762614266666611052
oct6035235352343700
91027532508865686
10213120231000000
11619a7867403955
121baa0166199a80
1391bc1c7c50b3c
143a8b1079238d2
151998b2db0b1a0
hexc1d4eba9c7c0

213120231000000 has 784 divisors, whose sum is σ = 751147125193728. Its totient is φ = 53203673600000.

The previous prime is 213120230999989. The next prime is 213120231000107. The reversal of 213120231000000 is 132021312.

213120231000000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×2131202310000002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 111 ways as a sum of consecutive naturals, for example, 3242967142 + ... + 3243032858.

Almost surely, 2213120231000000 is an apocalyptic number.

213120231000000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 213120231000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (375573562596864).

213120231000000 is an abundant number, since it is smaller than the sum of its proper divisors (538026894193728).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

213120231000000 is an frugal number, since it uses more digits than its factorization.

213120231000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 65832 (or 65797 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 213120231000000 its reverse (132021312), we get a palindrome (213120363021312).

The spelling of 213120231000000 in words is "two hundred thirteen trillion, one hundred twenty billion, two hundred thirty-one million", and thus it is an aban number.