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2131203011081 is a prime number
BaseRepresentation
bin11111000000110101100…
…110010011001000001001
321112202000012110101112212
4133000311212103020021
5234404200432323311
64311021112514505
7306655124461244
oct37006546231011
97482005411485
102131203011081
117519245a2a51
122a505b6aba35
13125c82745a81
1475217a3025b
153a686773c8b
hex1f035993209

2131203011081 has 2 divisors, whose sum is σ = 2131203011082. Its totient is φ = 2131203011080.

The previous prime is 2131203011053. The next prime is 2131203011131. The reversal of 2131203011081 is 1801103021312.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2049432749056 + 81770262025 = 1431584^2 + 285955^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2131203011081 is a prime.

It is a super-3 number, since 3×21312030110813 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (2131203011981) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065601505540 + 1065601505541.

It is an arithmetic number, because the mean of its divisors is an integer number (1065601505541).

Almost surely, 22131203011081 is an apocalyptic number.

It is an amenable number.

2131203011081 is a deficient number, since it is larger than the sum of its proper divisors (1).

2131203011081 is an equidigital number, since it uses as much as digits as its factorization.

2131203011081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 23.

Adding to 2131203011081 its reverse (1801103021312), we get a palindrome (3932306032393).

The spelling of 2131203011081 in words is "two trillion, one hundred thirty-one billion, two hundred three million, eleven thousand, eighty-one".