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2131203011131 is a prime number
BaseRepresentation
bin11111000000110101100…
…110010011001000111011
321112202000012110101121201
4133000311212103020323
5234404200432324011
64311021112515031
7306655124461345
oct37006546231073
97482005411551
102131203011131
117519245a2a97
122a505b6aba77
13125c82745abc
1475217a30295
153a686773cc1
hex1f03599323b

2131203011131 has 2 divisors, whose sum is σ = 2131203011132. Its totient is φ = 2131203011130.

The previous prime is 2131203011081. The next prime is 2131203011143. The reversal of 2131203011131 is 1311103021312.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2131203011131 - 29 = 2131203010619 is a prime.

It is a super-2 number, since 2×21312030111312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2131203011099 and 2131203011108.

It is not a weakly prime, because it can be changed into another prime (2131203411131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065601505565 + 1065601505566.

It is an arithmetic number, because the mean of its divisors is an integer number (1065601505566).

Almost surely, 22131203011131 is an apocalyptic number.

2131203011131 is a deficient number, since it is larger than the sum of its proper divisors (1).

2131203011131 is an equidigital number, since it uses as much as digits as its factorization.

2131203011131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 2131203011131 its reverse (1311103021312), we get a palindrome (3442306032443).

The spelling of 2131203011131 in words is "two trillion, one hundred thirty-one billion, two hundred three million, eleven thousand, one hundred thirty-one".