213120320117 has 2 divisors, whose sum is σ = 213120320118. Its totient is φ = 213120320116.

The previous prime is 213120320099. The next prime is 213120320129. The reversal of 213120320117 is 711023021312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 151880898961 + 61239421156 = 389719^2 + 247466^2 .

It is a cyclic number.

It is not a de Polignac number, because 213120320117 - 2⁶ = 213120320053 is a prime.

It is a super-4 number, since 4×213120320117⁴ (a number of 46 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 213120320092 and 213120320101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (213120320177) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106560160058 + 106560160059.

It is an arithmetic number, because the mean of its divisors is an integer number (106560160059).

Almost surely, 2^213120320117 is an apocalyptic number.

It is an amenable number.

213120320117 is a deficient number, since it is larger than the sum of its proper divisors (1).

213120320117 is an equidigital number, since it uses as much as digits as its factorization.

213120320117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 504, while the sum is 23.

Adding to 213120320117 its reverse (711023021312), we get a palindrome (924143341429).

The spelling of 213120320117 in words is "two hundred thirteen billion, one hundred twenty million, three hundred twenty thousand, one hundred seventeen".