Base | Representation |
---|---|
bin | 110000011101010011111000… |
… | …010111111001000111010111 |
3 | 1000221121010010012012221112101 |
4 | 300131103320113321013113 |
5 | 210413231132211142333 |
6 | 2033134102552102531 |
7 | 62614305166252033 |
oct | 6035237027710727 |
9 | 1027533105187471 |
10 | 213120444240343 |
11 | 619a796680a542 |
12 | 1baa0205694a47 |
13 | 91bc230192863 |
14 | 3a8b127d911c3 |
15 | 1998b426cd67d |
hex | c1d4f85f91d7 |
213120444240343 has 2 divisors, whose sum is σ = 213120444240344. Its totient is φ = 213120444240342.
The previous prime is 213120444240311. The next prime is 213120444240349. The reversal of 213120444240343 is 343042444021312.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 213120444240343 - 25 = 213120444240311 is a prime.
It is a super-2 number, since 2×2131204442403432 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (213120444240349) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106560222120171 + 106560222120172.
It is an arithmetic number, because the mean of its divisors is an integer number (106560222120172).
Almost surely, 2213120444240343 is an apocalyptic number.
213120444240343 is a deficient number, since it is larger than the sum of its proper divisors (1).
213120444240343 is an equidigital number, since it uses as much as digits as its factorization.
213120444240343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 221184, while the sum is 37.
Adding to 213120444240343 its reverse (343042444021312), we get a palindrome (556162888261655).
The spelling of 213120444240343 in words is "two hundred thirteen trillion, one hundred twenty billion, four hundred forty-four million, two hundred forty thousand, three hundred forty-three".
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