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21312131102981 is a prime number
BaseRepresentation
bin1001101100010000111100…
…00000001111100100000101
32210110102100001121211201022
410312020132000033210011
510243134221030243411
6113154354033240525
74326515322253415
oct466103600174405
983412301554638
1021312131102981
116877473446474
122482525703145
13bb7957756504
145397269d0645
1526e59dcc6edb
hex13621e00f905

21312131102981 has 2 divisors, whose sum is σ = 21312131102982. Its totient is φ = 21312131102980.

The previous prime is 21312131102923. The next prime is 21312131103013. The reversal of 21312131102981 is 18920113121312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 15553235050081 + 5758896052900 = 3943759^2 + 2399770^2 .

It is a cyclic number.

It is not a de Polignac number, because 21312131102981 - 230 = 21311057361157 is a prime.

It is a super-2 number, since 2×213121311029812 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21312131102681) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10656065551490 + 10656065551491.

It is an arithmetic number, because the mean of its divisors is an integer number (10656065551491).

Almost surely, 221312131102981 is an apocalyptic number.

It is an amenable number.

21312131102981 is a deficient number, since it is larger than the sum of its proper divisors (1).

21312131102981 is an equidigital number, since it uses as much as digits as its factorization.

21312131102981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 35.

The spelling of 21312131102981 in words is "twenty-one trillion, three hundred twelve billion, one hundred thirty-one million, one hundred two thousand, nine hundred eighty-one".