Base | Representation |
---|---|
bin | 11111000000110110101… |
… | …010100110001101101011 |
3 | 21112202001110011000011212 |
4 | 133000312222212031223 |
5 | 234404220023240201 |
6 | 4311022552343335 |
7 | 306655432610354 |
oct | 37006652461553 |
9 | 7482043130155 |
10 | 2131220915051 |
11 | 751933711518 |
12 | 2a50656a4b4b |
13 | 125c86374137 |
14 | 7521a170d2b |
15 | 3a68810dabb |
hex | 1f036aa636b |
2131220915051 has 2 divisors, whose sum is σ = 2131220915052. Its totient is φ = 2131220915050.
The previous prime is 2131220915041. The next prime is 2131220915071. The reversal of 2131220915051 is 1505190221312.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2131220915051 - 218 = 2131220652907 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2131220914999 and 2131220915017.
It is not a weakly prime, because it can be changed into another prime (2131220915011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065610457525 + 1065610457526.
It is an arithmetic number, because the mean of its divisors is an integer number (1065610457526).
Almost surely, 22131220915051 is an apocalyptic number.
2131220915051 is a deficient number, since it is larger than the sum of its proper divisors (1).
2131220915051 is an equidigital number, since it uses as much as digits as its factorization.
2131220915051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5400, while the sum is 32.
The spelling of 2131220915051 in words is "two trillion, one hundred thirty-one billion, two hundred twenty million, nine hundred fifteen thousand, fifty-one".
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