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213122221312 = 2873112131543
BaseRepresentation
bin1100011001111100010…
…0110000010100000000
3202101002212001121002011
43012133010300110000
511442433242040222
6241523524502304
721253236664000
oct3063704602400
9671085047064
10213122221312
1182425a35300
123537a24a994
1317135b14b80
14a45ab84000
1558254b9c77
hex319f130500

213122221312 has 432 divisors, whose sum is σ = 587635283200. Its totient is φ = 76597678080.

The previous prime is 213122221307. The next prime is 213122221313.

213122221312 is nontrivially palindromic in base 10.

It is a super-2 number, since 2×2131222213122 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (22).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (213122221313) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 138121213 + ... + 138122755.

Almost surely, 2213122221312 is an apocalyptic number.

213122221312 is a gapful number since it is divisible by the number (22) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 213122221312, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (293817641600).

213122221312 is an abundant number, since it is smaller than the sum of its proper divisors (374513061888).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

213122221312 is a wasteful number, since it uses less digits than its factorization.

213122221312 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1615 (or 1576 counting only the distinct ones).

The product of its digits is 576, while the sum is 22.

Multiplying 213122221312 by its sum of digits (22), we get a palindrome (4688688868864).

It can be divided in two parts, 213122 and 221312, that added together give a palindrome (434434).

The spelling of 213122221312 in words is "two hundred thirteen billion, one hundred twenty-two million, two hundred twenty-one thousand, three hundred twelve".