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2131223100133 is a prime number
BaseRepresentation
bin11111000000110110110…
…010111011101011100101
321112202001121021000112211
4133000312302323223211
5234404221103201013
64311023111243421
7306655460311021
oct37006662735345
97482047230484
102131223100133
11751934974176
122a5066379571
13125c8695a89a
147521a57d381
153a6883e123d
hex1f036cbbae5

2131223100133 has 2 divisors, whose sum is σ = 2131223100134. Its totient is φ = 2131223100132.

The previous prime is 2131223100109. The next prime is 2131223100161. The reversal of 2131223100133 is 3310013221312.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2107093205889 + 24129894244 = 1451583^2 + 155338^2 .

It is a cyclic number.

It is not a de Polignac number, because 2131223100133 - 213 = 2131223091941 is a prime.

It is a super-2 number, since 2×21312231001332 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2131223100233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065611550066 + 1065611550067.

It is an arithmetic number, because the mean of its divisors is an integer number (1065611550067).

Almost surely, 22131223100133 is an apocalyptic number.

It is an amenable number.

2131223100133 is a deficient number, since it is larger than the sum of its proper divisors (1).

2131223100133 is an equidigital number, since it uses as much as digits as its factorization.

2131223100133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 2131223100133 its reverse (3310013221312), we get a palindrome (5441236321445).

The spelling of 2131223100133 in words is "two trillion, one hundred thirty-one billion, two hundred twenty-three million, one hundred thousand, one hundred thirty-three".