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21312251030113 is a prime number
BaseRepresentation
bin1001101100010001001010…
…01001101110101001100001
32210110102122102021202210221
410312020211021232221201
510243134442230430423
6113154413555523041
74326521306522251
oct466104511565141
983412572252727
1021312251030113
1168775251084aa
1224825598b9481
13bb7976556204
145397388cb961
1526e5a95b5e5d
hex13622526ea61

21312251030113 has 2 divisors, whose sum is σ = 21312251030114. Its totient is φ = 21312251030112.

The previous prime is 21312251030093. The next prime is 21312251030123. The reversal of 21312251030113 is 31103015221312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 16943950387809 + 4368300642304 = 4116303^2 + 2090048^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-21312251030113 is a prime.

It is not a weakly prime, because it can be changed into another prime (21312251030123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10656125515056 + 10656125515057.

It is an arithmetic number, because the mean of its divisors is an integer number (10656125515057).

Almost surely, 221312251030113 is an apocalyptic number.

It is an amenable number.

21312251030113 is a deficient number, since it is larger than the sum of its proper divisors (1).

21312251030113 is an equidigital number, since it uses as much as digits as its factorization.

21312251030113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1080, while the sum is 25.

Adding to 21312251030113 its reverse (31103015221312), we get a palindrome (52415266251425).

The spelling of 21312251030113 in words is "twenty-one trillion, three hundred twelve billion, two hundred fifty-one million, thirty thousand, one hundred thirteen".