Base | Representation |
---|---|
bin | 1001101100010001001010… |
… | …01001101110101001100001 |
3 | 2210110102122102021202210221 |
4 | 10312020211021232221201 |
5 | 10243134442230430423 |
6 | 113154413555523041 |
7 | 4326521306522251 |
oct | 466104511565141 |
9 | 83412572252727 |
10 | 21312251030113 |
11 | 68775251084aa |
12 | 24825598b9481 |
13 | bb7976556204 |
14 | 5397388cb961 |
15 | 26e5a95b5e5d |
hex | 13622526ea61 |
21312251030113 has 2 divisors, whose sum is σ = 21312251030114. Its totient is φ = 21312251030112.
The previous prime is 21312251030093. The next prime is 21312251030123. The reversal of 21312251030113 is 31103015221312.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 16943950387809 + 4368300642304 = 4116303^2 + 2090048^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21312251030113 is a prime.
It is not a weakly prime, because it can be changed into another prime (21312251030123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10656125515056 + 10656125515057.
It is an arithmetic number, because the mean of its divisors is an integer number (10656125515057).
Almost surely, 221312251030113 is an apocalyptic number.
It is an amenable number.
21312251030113 is a deficient number, since it is larger than the sum of its proper divisors (1).
21312251030113 is an equidigital number, since it uses as much as digits as its factorization.
21312251030113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1080, while the sum is 25.
Adding to 21312251030113 its reverse (31103015221312), we get a palindrome (52415266251425).
The spelling of 21312251030113 in words is "twenty-one trillion, three hundred twelve billion, two hundred fifty-one million, thirty thousand, one hundred thirteen".
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