Base | Representation |
---|---|
bin | 11111000000110111011… |
… | …001000101110100011100 |
3 | 21112202002022002020002021 |
4 | 133000313121011310130 |
5 | 234404231133300012 |
6 | 4311024105505524 |
7 | 306655641322210 |
oct | 37006731056434 |
9 | 7482068066067 |
10 | 2131233103132 |
11 | 75193a586611 |
12 | 2a50697a22a4 |
13 | 125c88a50913 |
14 | 7521ba24940 |
15 | 3a68921a007 |
hex | 1f037645d1c |
2131233103132 has 12 divisors (see below), whose sum is σ = 4262466206320. Its totient is φ = 913385615616.
The previous prime is 2131233103127. The next prime is 2131233103133. The reversal of 2131233103132 is 2313013321312.
2131233103132 is an admirable number.
It is a junction number, because it is equal to n+sod(n) for n = 2131233103097 and 2131233103106.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2131233103133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 38057733957 + ... + 38057734012.
Almost surely, 22131233103132 is an apocalyptic number.
It is an amenable number.
2131233103132 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2131233103132 is a wasteful number, since it uses less digits than its factorization.
2131233103132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 76115467980 (or 76115467978 counting only the distinct ones).
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 2131233103132 its reverse (2313013321312), we get a palindrome (4444246424444).
The spelling of 2131233103132 in words is "two trillion, one hundred thirty-one billion, two hundred thirty-three million, one hundred three thousand, one hundred thirty-two".
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