Base | Representation |
---|---|
bin | 1001101100010001011111… |
… | …11100111011110010100011 |
3 | 2210110110010001020110002002 |
4 | 10312020233330323302203 |
5 | 10243140330122203233 |
6 | 113154443551314215 |
7 | 4326525636616442 |
oct | 466105774736243 |
9 | 83413101213062 |
10 | 21312432225443 |
11 | 6877608417207 |
12 | 24825aa51b96b |
13 | bb79a4c58198 |
14 | 5397549b6d59 |
15 | 26e5ba4586e8 |
hex | 13622ff3bca3 |
21312432225443 has 2 divisors, whose sum is σ = 21312432225444. Its totient is φ = 21312432225442.
The previous prime is 21312432225397. The next prime is 21312432225529. The reversal of 21312432225443 is 34452223421312.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21312432225443 - 212 = 21312432221347 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 21312432225397 and 21312432225406.
It is not a weakly prime, because it can be changed into another prime (21312432225143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10656216112721 + 10656216112722.
It is an arithmetic number, because the mean of its divisors is an integer number (10656216112722).
Almost surely, 221312432225443 is an apocalyptic number.
21312432225443 is a deficient number, since it is larger than the sum of its proper divisors (1).
21312432225443 is an equidigital number, since it uses as much as digits as its factorization.
21312432225443 is an evil number, because the sum of its binary digits is even.
The product of its digits is 276480, while the sum is 38.
Adding to 21312432225443 its reverse (34452223421312), we get a palindrome (55764655646755).
The spelling of 21312432225443 in words is "twenty-one trillion, three hundred twelve billion, four hundred thirty-two million, two hundred twenty-five thousand, four hundred forty-three".
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