Base | Representation |
---|---|
bin | 11111000000111100000… |
… | …010001111100111001100 |
3 | 21112202021201122210111220 |
4 | 133000330002033213030 |
5 | 234404411104000022 |
6 | 4311035531243340 |
7 | 306660605405625 |
oct | 37007402174714 |
9 | 7482251583456 |
10 | 2131311000012 |
11 | 75197a5506a7 |
12 | 2a508b8a9550 |
13 | 125c9bc2594c |
14 | 75228100a4c |
15 | 3a690ea585c |
hex | 1f03c08f9cc |
2131311000012 has 12 divisors (see below), whose sum is σ = 4973059000056. Its totient is φ = 710437000000.
The previous prime is 2131311000001. The next prime is 2131311000031. The reversal of 2131311000012 is 2100001131312.
It is a happy number.
It is a tau number, because it is divible by the number of its divisors (12).
It is a junction number, because it is equal to n+sod(n) for n = 2131310999955 and 2131311000000.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 88804624989 + ... + 88804625012.
It is an arithmetic number, because the mean of its divisors is an integer number (414421583338).
Almost surely, 22131311000012 is an apocalyptic number.
It is an amenable number.
2131311000012 is an abundant number, since it is smaller than the sum of its proper divisors (2841748000044).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2131311000012 is a wasteful number, since it uses less digits than its factorization.
2131311000012 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 177609250008 (or 177609250006 counting only the distinct ones).
The product of its (nonzero) digits is 36, while the sum is 15.
Adding to 2131311000012 its reverse (2100001131312), we get a palindrome (4231312131324).
The spelling of 2131311000012 in words is "two trillion, one hundred thirty-one billion, three hundred eleven million, twelve", and thus it is an aban number.
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