Search a number
-
+
213131113110000 = 24355487708277
BaseRepresentation
bin110000011101011101110100…
…010010011001100111110000
31000221122010122201120200100000
4300131131310102121213300
5210413420004424010000
62033143025351030000
762615133445201221
oct6035356422314760
91027563581520300
10213131113110000
1161a01441041198
121baa22a266b300
1391c024060ca97
143a8b85aca7248
151999069160000
hexc1d7744999f0

213131113110000 has 300 divisors, whose sum is σ = 772955863191512. Its totient is φ = 56834962848000.

The previous prime is 213131113109989. The next prime is 213131113110023. The reversal of 213131113110000 is 11311131312.

213131113110000 is a `hidden beast` number, since 213 + 1 + 311 + 131 + 10 + 0 + 0 + 0 = 666.

213131113110000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a tau number, because it is divible by the number of its divisors (300).

It is a super-2 number, since 2×2131311131100002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 59 ways as a sum of consecutive naturals, for example, 41424139 + ... + 46284138.

Almost surely, 2213131113110000 is an apocalyptic number.

213131113110000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

213131113110000 is an abundant number, since it is smaller than the sum of its proper divisors (559824750081512).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

213131113110000 is an frugal number, since it uses more digits than its factorization.

213131113110000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 87708320 (or 87708287 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 18.

Adding to 213131113110000 its reverse (11311131312), we get a palindrome (213142424241312).

The spelling of 213131113110000 in words is "two hundred thirteen trillion, one hundred thirty-one billion, one hundred thirteen million, one hundred ten thousand".