21313114019 has 2 divisors, whose sum is σ = 21313114020. Its totient is φ = 21313114018.

The previous prime is 21313114007. The next prime is 21313114021. The reversal of 21313114019 is 91041131312.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-21313114019 is a prime.

It is a super-2 number, since 2×21313114019² (a number of 21 digits) contains 22 as substring.

Together with 21313114021, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (21313114919) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10656557009 + 10656557010.

It is an arithmetic number, because the mean of its divisors is an integer number (10656557010).

Almost surely, 2^21313114019 is an apocalyptic number.

21313114019 is a deficient number, since it is larger than the sum of its proper divisors (1).

21313114019 is an equidigital number, since it uses as much as digits as its factorization.

21313114019 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 26.

The spelling of 21313114019 in words is "twenty-one billion, three hundred thirteen million, one hundred fourteen thousand, nineteen".