Base | Representation |
---|---|
bin | 110000011101011101111010… |
… | …001001000011100000110100 |
3 | 1000221122010220120101102211222 |
4 | 300131131322021003200310 |
5 | 210413420210044322234 |
6 | 2033143043220045512 |
7 | 62615136050042621 |
oct | 6035357211034064 |
9 | 1027563816342758 |
10 | 213131211323444 |
11 | 61a01491522427 |
12 | 1baa230b533898 |
13 | 91c0257a7934b |
14 | 3a8b869d51348 |
15 | 1999072ab042e |
hex | c1d77a243834 |
213131211323444 has 24 divisors (see below), whose sum is σ = 373071622694400. Its totient is φ = 106539322119776.
The previous prime is 213131211323431. The next prime is 213131211323453. The reversal of 213131211323444 is 444323112131312.
It is a super-3 number, since 3×2131312113234443 (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 291275957 + ... + 292006755.
It is an arithmetic number, because the mean of its divisors is an integer number (15544650945600).
Almost surely, 2213131211323444 is an apocalyptic number.
It is an amenable number.
213131211323444 is a deficient number, since it is larger than the sum of its proper divisors (159940411370956).
213131211323444 is a wasteful number, since it uses less digits than its factorization.
213131211323444 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 748687 (or 748685 counting only the distinct ones).
The product of its digits is 41472, while the sum is 35.
Adding to 213131211323444 its reverse (444323112131312), we get a palindrome (657454323454756).
The spelling of 213131211323444 in words is "two hundred thirteen trillion, one hundred thirty-one billion, two hundred eleven million, three hundred twenty-three thousand, four hundred forty-four".
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