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213131211323971 is a prime number
BaseRepresentation
bin110000011101011101111010…
…001001000011101001000011
31000221122010220120101110120111
4300131131322021003221003
5210413420210044331341
62033143043220052151
762615136050044303
oct6035357211035103
91027563816343514
10213131211323971
1161a01491522866
121baa230b534057
1391c0257a79665
143a8b869d51603
151999072ab0681
hexc1d77a243a43

213131211323971 has 2 divisors, whose sum is σ = 213131211323972. Its totient is φ = 213131211323970.

The previous prime is 213131211323969. The next prime is 213131211323983. The reversal of 213131211323971 is 179323112131312.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 213131211323971 - 21 = 213131211323969 is a prime.

Together with 213131211323969, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (213131211323071) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106565605661985 + 106565605661986.

It is an arithmetic number, because the mean of its divisors is an integer number (106565605661986).

Almost surely, 2213131211323971 is an apocalyptic number.

213131211323971 is a deficient number, since it is larger than the sum of its proper divisors (1).

213131211323971 is an equidigital number, since it uses as much as digits as its factorization.

213131211323971 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 40824, while the sum is 40.

The spelling of 213131211323971 in words is "two hundred thirteen trillion, one hundred thirty-one billion, two hundred eleven million, three hundred twenty-three thousand, nine hundred seventy-one".