Base | Representation |
---|---|
bin | 10011110110010111… |
… | …000111011010110001 |
3 | 2001000100101212202121 |
4 | 103312113013122301 |
5 | 322122124432032 |
6 | 13442514114241 |
7 | 1353105364543 |
oct | 236627073261 |
9 | 61010355677 |
10 | 21313124017 |
11 | 9047780589 |
12 | 416987b981 |
13 | 20187593b3 |
14 | 1062861693 |
15 | 84b19ea97 |
hex | 4f65c76b1 |
21313124017 has 2 divisors, whose sum is σ = 21313124018. Its totient is φ = 21313124016.
The previous prime is 21313124003. The next prime is 21313124039. The reversal of 21313124017 is 71042131312.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 20242460176 + 1070663841 = 142276^2 + 32721^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21313124017 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 21313123982 and 21313124000.
It is not a weakly prime, because it can be changed into another prime (21313124057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10656562008 + 10656562009.
It is an arithmetic number, because the mean of its divisors is an integer number (10656562009).
Almost surely, 221313124017 is an apocalyptic number.
It is an amenable number.
21313124017 is a deficient number, since it is larger than the sum of its proper divisors (1).
21313124017 is an equidigital number, since it uses as much as digits as its factorization.
21313124017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 21313124017 its reverse (71042131312), we get a palindrome (92355255329).
The spelling of 21313124017 in words is "twenty-one billion, three hundred thirteen million, one hundred twenty-four thousand, seventeen".
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