Base | Representation |
---|---|
bin | 11111000000111100001… |
… | …110100010100001111111 |
3 | 21112202021221201112221101 |
4 | 133000330032202201333 |
5 | 234404412420120411 |
6 | 4311040124313531 |
7 | 306660644662024 |
oct | 37007416424177 |
9 | 7482257645841 |
10 | 2131314223231 |
11 | 751981352316 |
12 | 2a50909a28a7 |
13 | 125c9c7b3a8b |
14 | 752286dd54b |
15 | 3a6913e08c1 |
hex | 1f03c3a287f |
2131314223231 has 2 divisors, whose sum is σ = 2131314223232. Its totient is φ = 2131314223230.
The previous prime is 2131314223133. The next prime is 2131314223273. The reversal of 2131314223231 is 1323224131312.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2131314223231 is a prime.
It is a super-2 number, since 2×21313142232312 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 2131314223231.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2131314223531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065657111615 + 1065657111616.
It is an arithmetic number, because the mean of its divisors is an integer number (1065657111616).
Almost surely, 22131314223231 is an apocalyptic number.
2131314223231 is a deficient number, since it is larger than the sum of its proper divisors (1).
2131314223231 is an equidigital number, since it uses as much as digits as its factorization.
2131314223231 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5184, while the sum is 28.
Adding to 2131314223231 its reverse (1323224131312), we get a palindrome (3454538354543).
The spelling of 2131314223231 in words is "two trillion, one hundred thirty-one billion, three hundred fourteen million, two hundred twenty-three thousand, two hundred thirty-one".
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