Base | Representation |
---|---|
bin | 110000011101011110101001… |
… | …111011010000100101100111 |
3 | 1000221122012222102220111122202 |
4 | 300131132221323100211213 |
5 | 210413423330312411401 |
6 | 2033143254535045115 |
7 | 62615164653225155 |
oct | 6035365173204547 |
9 | 1027565872814582 |
10 | 213132013013351 |
11 | 61a01863007973 |
12 | 1baa24b3b1079b |
13 | 91c0354ba1483 |
14 | 3a8b9045da3d5 |
15 | 19990bd16d06b |
hex | c1d7a9ed0967 |
213132013013351 has 2 divisors, whose sum is σ = 213132013013352. Its totient is φ = 213132013013350.
The previous prime is 213132013013321. The next prime is 213132013013357. The reversal of 213132013013351 is 153310310231312.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 213132013013351 - 234 = 213114833144167 is a prime.
It is a super-2 number, since 2×2131320130133512 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (213132013013357) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106566006506675 + 106566006506676.
It is an arithmetic number, because the mean of its divisors is an integer number (106566006506676).
Almost surely, 2213132013013351 is an apocalyptic number.
213132013013351 is a deficient number, since it is larger than the sum of its proper divisors (1).
213132013013351 is an equidigital number, since it uses as much as digits as its factorization.
213132013013351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4860, while the sum is 29.
Adding to 213132013013351 its reverse (153310310231312), we get a palindrome (366442323244663).
The spelling of 213132013013351 in words is "two hundred thirteen trillion, one hundred thirty-two billion, thirteen million, thirteen thousand, three hundred fifty-one".
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