Base | Representation |
---|---|
bin | 1001101100010100101100… |
… | …11010100001111100100001 |
3 | 2210110121112211220110002022 |
4 | 10312022112122201330201 |
5 | 10243202340210304222 |
6 | 113155330320231225 |
7 | 4326616352310014 |
oct | 466122632417441 |
9 | 83417484813068 |
10 | 21314151259937 |
11 | 687830a800278 |
12 | 24829aa16b515 |
13 | bb7bba13a563 |
14 | 53987901537b |
15 | 26e66b31c042 |
hex | 1362966a1f21 |
21314151259937 has 2 divisors, whose sum is σ = 21314151259938. Its totient is φ = 21314151259936.
The previous prime is 21314151259837. The next prime is 21314151259943. The reversal of 21314151259937 is 73995215141312.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 16120875436561 + 5193275823376 = 4015081^2 + 2278876^2 .
It is a cyclic number.
It is not a de Polignac number, because 21314151259937 - 218 = 21314150997793 is a prime.
It is not a weakly prime, because it can be changed into another prime (21314151259967) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10657075629968 + 10657075629969.
It is an arithmetic number, because the mean of its divisors is an integer number (10657075629969).
Almost surely, 221314151259937 is an apocalyptic number.
It is an amenable number.
21314151259937 is a deficient number, since it is larger than the sum of its proper divisors (1).
21314151259937 is an equidigital number, since it uses as much as digits as its factorization.
21314151259937 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2041200, while the sum is 53.
The spelling of 21314151259937 in words is "twenty-one trillion, three hundred fourteen billion, one hundred fifty-one million, two hundred fifty-nine thousand, nine hundred thirty-seven".
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