Search a number
-
+
21314151259937 is a prime number
BaseRepresentation
bin1001101100010100101100…
…11010100001111100100001
32210110121112211220110002022
410312022112122201330201
510243202340210304222
6113155330320231225
74326616352310014
oct466122632417441
983417484813068
1021314151259937
11687830a800278
1224829aa16b515
13bb7bba13a563
1453987901537b
1526e66b31c042
hex1362966a1f21

21314151259937 has 2 divisors, whose sum is σ = 21314151259938. Its totient is φ = 21314151259936.

The previous prime is 21314151259837. The next prime is 21314151259943. The reversal of 21314151259937 is 73995215141312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 16120875436561 + 5193275823376 = 4015081^2 + 2278876^2 .

It is a cyclic number.

It is not a de Polignac number, because 21314151259937 - 218 = 21314150997793 is a prime.

It is not a weakly prime, because it can be changed into another prime (21314151259967) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10657075629968 + 10657075629969.

It is an arithmetic number, because the mean of its divisors is an integer number (10657075629969).

Almost surely, 221314151259937 is an apocalyptic number.

It is an amenable number.

21314151259937 is a deficient number, since it is larger than the sum of its proper divisors (1).

21314151259937 is an equidigital number, since it uses as much as digits as its factorization.

21314151259937 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2041200, while the sum is 53.

The spelling of 21314151259937 in words is "twenty-one trillion, three hundred fourteen billion, one hundred fifty-one million, two hundred fifty-nine thousand, nine hundred thirty-seven".