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213143342044 = 22234353878499
BaseRepresentation
bin1100011010000001010…
…1010100101111011100
3202101011022210122021111
43012200111110233130
511443004143421134
6241530001311404
721253614341323
oct3064025245734
9671138718244
10213143342044
1182436950656
1235385335564
131713a2cb449
14a45d8c10ba
15582728cc64
hex31a0554bdc

213143342044 has 24 divisors (see below), whose sum is σ = 398269872000. Its totient is φ = 99567464304.

The previous prime is 213143342039. The next prime is 213143342047. The reversal of 213143342044 is 440243341312.

It is a super-3 number, since 3×2131433420443 (a number of 35 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 213143341997 and 213143342015.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (213143342047) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 26935294 + ... + 26943205.

It is an arithmetic number, because the mean of its divisors is an integer number (16594578000).

Almost surely, 2213143342044 is an apocalyptic number.

It is an amenable number.

213143342044 is a deficient number, since it is larger than the sum of its proper divisors (185126529956).

213143342044 is a wasteful number, since it uses less digits than its factorization.

213143342044 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 53878569 (or 53878567 counting only the distinct ones).

The product of its (nonzero) digits is 27648, while the sum is 31.

Adding to 213143342044 its reverse (440243341312), we get a palindrome (653386683356).

The spelling of 213143342044 in words is "two hundred thirteen billion, one hundred forty-three million, three hundred forty-two thousand, forty-four".

Divisors: 1 2 4 23 43 46 86 92 172 989 1978 3956 53878499 107756998 215513996 1239205477 2316775457 2478410954 4633550914 4956821908 9267101828 53285835511 106571671022 213143342044