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2131453541233 is a prime number
BaseRepresentation
bin11111000001000100100…
…001111111101101110001
321112202122122212122022101
4133001010201333231301
5234410204101304413
64311102022340401
7306664256111662
oct37010441775561
97482578778271
102131453541233
11751a42a58a65
122a510b58a701
13125cc2612873
147523d007369
153a69d75eedd
hex1f04487fb71

2131453541233 has 2 divisors, whose sum is σ = 2131453541234. Its totient is φ = 2131453541232.

The previous prime is 2131453541219. The next prime is 2131453541281. The reversal of 2131453541233 is 3321453541312.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1683394666849 + 448058874384 = 1297457^2 + 669372^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2131453541233 is a prime.

It is a super-3 number, since 3×21314535412333 (a number of 38 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2131453541192 and 2131453541201.

It is not a weakly prime, because it can be changed into another prime (2131453541033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065726770616 + 1065726770617.

It is an arithmetic number, because the mean of its divisors is an integer number (1065726770617).

Almost surely, 22131453541233 is an apocalyptic number.

It is an amenable number.

2131453541233 is a deficient number, since it is larger than the sum of its proper divisors (1).

2131453541233 is an equidigital number, since it uses as much as digits as its factorization.

2131453541233 is an evil number, because the sum of its binary digits is even.

The product of its digits is 129600, while the sum is 37.

The spelling of 2131453541233 in words is "two trillion, one hundred thirty-one billion, four hundred fifty-three million, five hundred forty-one thousand, two hundred thirty-three".