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2132011031 is a prime number
BaseRepresentation
bin111111100010011…
…1110100000010111
312111120202101022112
41333010332200113
513331243323111
6551320221235
7103555536413
oct17704764027
95446671275
102132011031
119a4512497
124b600a81b
1327c9182b7
1416321dd43
15c728be8b
hex7f13e817

2132011031 has 2 divisors, whose sum is σ = 2132011032. Its totient is φ = 2132011030.

The previous prime is 2132010989. The next prime is 2132011043. The reversal of 2132011031 is 1301102312.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2132011031 - 222 = 2127816727 is a prime.

It is a super-2 number, since 2×21320110312 = 9090942072611365922, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2132010997 and 2132011015.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2132011331) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1066005515 + 1066005516.

It is an arithmetic number, because the mean of its divisors is an integer number (1066005516).

Almost surely, 22132011031 is an apocalyptic number.

2132011031 is a deficient number, since it is larger than the sum of its proper divisors (1).

2132011031 is an equidigital number, since it uses as much as digits as its factorization.

2132011031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36, while the sum is 14.

The square root of 2132011031 is about 46173.7049737185. The cubic root of 2132011031 is about 1287.0531518223.

Adding to 2132011031 its reverse (1301102312), we get a palindrome (3433113343).

The spelling of 2132011031 in words is "two billion, one hundred thirty-two million, eleven thousand, thirty-one".