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213201343311223 is a prime number
BaseRepresentation
bin110000011110011111001110…
…010101010110110101110111
31000221212211221012002112220211
4300132133032111112311313
5210421042322341424343
62033235202304010251
762623201016102401
oct6036371625266567
91027784835075824
10213201343311223
1161a29200173903
121bab3a22600987
1391c6a53657177
143a910002c3b71
15199acc9a9379d
hexc1e7ce556d77

213201343311223 has 2 divisors, whose sum is σ = 213201343311224. Its totient is φ = 213201343311222.

The previous prime is 213201343311193. The next prime is 213201343311247. The reversal of 213201343311223 is 322113343102312.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 213201343311223 - 25 = 213201343311191 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (213201343411223) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106600671655611 + 106600671655612.

It is an arithmetic number, because the mean of its divisors is an integer number (106600671655612).

Almost surely, 2213201343311223 is an apocalyptic number.

213201343311223 is a deficient number, since it is larger than the sum of its proper divisors (1).

213201343311223 is an equidigital number, since it uses as much as digits as its factorization.

213201343311223 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 213201343311223 its reverse (322113343102312), we get a palindrome (535314686413535).

The spelling of 213201343311223 in words is "two hundred thirteen trillion, two hundred one billion, three hundred forty-three million, three hundred eleven thousand, two hundred twenty-three".