Base | Representation |
---|---|
bin | 11111000001100111000… |
… | …001000110100111001101 |
3 | 21112211010222120112221111 |
4 | 133001213001012213031 |
5 | 234412400210340133 |
6 | 4311235251332021 |
7 | 310014513006214 |
oct | 37014701064715 |
9 | 7484128515844 |
10 | 2132032121293 |
11 | 75220a6067a8 |
12 | 2a52512b1011 |
13 | 12608544b929 |
14 | 75295bb607b |
15 | 3a6d444b1cd |
hex | 1f0670469cd |
2132032121293 has 2 divisors, whose sum is σ = 2132032121294. Its totient is φ = 2132032121292.
The previous prime is 2132032121267. The next prime is 2132032121341. The reversal of 2132032121293 is 3921212302312.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1557099674244 + 574932447049 = 1247838^2 + 758243^2 .
It is a cyclic number.
It is not a de Polignac number, because 2132032121293 - 225 = 2131998566861 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2132032121393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1066016060646 + 1066016060647.
It is an arithmetic number, because the mean of its divisors is an integer number (1066016060647).
Almost surely, 22132032121293 is an apocalyptic number.
It is an amenable number.
2132032121293 is a deficient number, since it is larger than the sum of its proper divisors (1).
2132032121293 is an equidigital number, since it uses as much as digits as its factorization.
2132032121293 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7776, while the sum is 31.
The spelling of 2132032121293 in words is "two trillion, one hundred thirty-two billion, thirty-two million, one hundred twenty-one thousand, two hundred ninety-three".
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