Base | Representation |
---|---|
bin | 1001101100100000011001… |
… | …10101111011110000101111 |
3 | 2210111012202122100010022012 |
4 | 10312100030311323300233 |
5 | 10243303221334403401 |
6 | 113202245522311435 |
7 | 4330231131253466 |
oct | 466201465736057 |
9 | 83435678303265 |
10 | 21320433122351 |
11 | 687aa43747500 |
12 | 2484061ab857b |
13 | bb867b7235cc |
14 | 539cb34359dd |
15 | 26e8d7a7e8bb |
hex | 13640cd7bc2f |
21320433122351 has 48 divisors (see below), whose sum is σ = 23805770692704. Its totient is φ = 19077901920000.
The previous prime is 21320433122203. The next prime is 21320433122353. The reversal of 21320433122351 is 15322133402312.
It is a de Polignac number, because none of the positive numbers 2k-21320433122351 is a prime.
It is a super-2 number, since 2×213204331223512 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (21320433122353) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 2570890961 + ... + 2570899253.
It is an arithmetic number, because the mean of its divisors is an integer number (495953556098).
Almost surely, 221320433122351 is an apocalyptic number.
21320433122351 is a deficient number, since it is larger than the sum of its proper divisors (2485337570353).
21320433122351 is a wasteful number, since it uses less digits than its factorization.
21320433122351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9624 (or 9613 counting only the distinct ones).
The product of its (nonzero) digits is 25920, while the sum is 32.
Adding to 21320433122351 its reverse (15322133402312), we get a palindrome (36642566524663).
The spelling of 21320433122351 in words is "twenty-one trillion, three hundred twenty billion, four hundred thirty-three million, one hundred twenty-two thousand, three hundred fifty-one".
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