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213214053121 is a prime number
BaseRepresentation
bin1100011010010010001…
…1000100001100000001
3202101100020212010122021
43012210203010030001
511443130244144441
6241541005041441
721255433356136
oct3064443041401
9671306763567
10213214053121
1182472857963
12353a4b56281
131714bb58814
14a46904a58d
15582d5a93d1
hex31a48c4301

213214053121 has 2 divisors, whose sum is σ = 213214053122. Its totient is φ = 213214053120.

The previous prime is 213214053103. The next prime is 213214053137. The reversal of 213214053121 is 121350412312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 123612012225 + 89602040896 = 351585^2 + 299336^2 .

It is a cyclic number.

It is not a de Polignac number, because 213214053121 - 211 = 213214051073 is a prime.

It is not a weakly prime, because it can be changed into another prime (213214053181) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106607026560 + 106607026561.

It is an arithmetic number, because the mean of its divisors is an integer number (106607026561).

Almost surely, 2213214053121 is an apocalyptic number.

It is an amenable number.

213214053121 is a deficient number, since it is larger than the sum of its proper divisors (1).

213214053121 is an equidigital number, since it uses as much as digits as its factorization.

213214053121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 213214053121 its reverse (121350412312), we get a palindrome (334564465433).

The spelling of 213214053121 in words is "two hundred thirteen billion, two hundred fourteen million, fifty-three thousand, one hundred twenty-one".