Base | Representation |
---|---|
bin | 11111000001111110001… |
… | …101110001111001111101 |
3 | 21112212011002220220122011 |
4 | 133001332031301321331 |
5 | 234414144324222232 |
6 | 4311342033251221 |
7 | 310030250104231 |
oct | 37017615617175 |
9 | 7485132826564 |
10 | 2132421320317 |
11 | 75239a274792 |
12 | 2a533b703b11 |
13 | 126117c7ac02 |
14 | 752d17685c1 |
15 | 3a7086c9547 |
hex | 1f07e371e7d |
2132421320317 has 2 divisors, whose sum is σ = 2132421320318. Its totient is φ = 2132421320316.
The previous prime is 2132421320303. The next prime is 2132421320333. The reversal of 2132421320317 is 7130231242312.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1556877567001 + 575543753316 = 1247749^2 + 758646^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2132421320317 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2132421320357) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1066210660158 + 1066210660159.
It is an arithmetic number, because the mean of its divisors is an integer number (1066210660159).
Almost surely, 22132421320317 is an apocalyptic number.
It is an amenable number.
2132421320317 is a deficient number, since it is larger than the sum of its proper divisors (1).
2132421320317 is an equidigital number, since it uses as much as digits as its factorization.
2132421320317 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12096, while the sum is 31.
Adding to 2132421320317 its reverse (7130231242312), we get a palindrome (9262652562629).
The spelling of 2132421320317 in words is "two trillion, one hundred thirty-two billion, four hundred twenty-one million, three hundred twenty thousand, three hundred seventeen".
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