Base | Representation |
---|---|
bin | 10011110111000010… |
… | …010011000111100011 |
3 | 2001001010201000001002 |
4 | 103313002103013203 |
5 | 322133024203011 |
6 | 13444000502215 |
7 | 1353303533024 |
oct | 236702230743 |
9 | 61033630032 |
10 | 21324444131 |
11 | 9053102551 |
12 | 417161a96b |
13 | 201abc0aa3 |
14 | 106416ac4b |
15 | 84c188c3b |
hex | 4f70931e3 |
21324444131 has 2 divisors, whose sum is σ = 21324444132. Its totient is φ = 21324444130.
The previous prime is 21324444103. The next prime is 21324444133. The reversal of 21324444131 is 13144442312.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21324444131 - 26 = 21324444067 is a prime.
It is a super-2 number, since 2×213244441312 (a number of 21 digits) contains 22 as substring.
It is a Sophie Germain prime.
Together with 21324444133, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 21324444094 and 21324444103.
It is not a weakly prime, because it can be changed into another prime (21324444133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10662222065 + 10662222066.
It is an arithmetic number, because the mean of its divisors is an integer number (10662222066).
Almost surely, 221324444131 is an apocalyptic number.
21324444131 is a deficient number, since it is larger than the sum of its proper divisors (1).
21324444131 is an equidigital number, since it uses as much as digits as its factorization.
21324444131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 9216, while the sum is 29.
Adding to 21324444131 its reverse (13144442312), we get a palindrome (34468886443).
The spelling of 21324444131 in words is "twenty-one billion, three hundred twenty-four million, four hundred forty-four thousand, one hundred thirty-one".
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