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21325129215881 is a prime number
BaseRepresentation
bin1001101100101001001001…
…10000000110111110001001
32210111122212220212101120012
410312110210300012332021
510243342331034402011
6113204343520041305
74330455403351331
oct466244460067611
983448786771505
1021325129215881
116881a33552037
122484b52763235
13bb8c4961728a
1453a1dadc80c1
1526eaaeea4a8b
hex136524c06f89

21325129215881 has 2 divisors, whose sum is σ = 21325129215882. Its totient is φ = 21325129215880.

The previous prime is 21325129215833. The next prime is 21325129215883. The reversal of 21325129215881 is 18851292152312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 16255048380025 + 5070080835856 = 4031755^2 + 2251684^2 .

It is a cyclic number.

It is not a de Polignac number, because 21325129215881 - 238 = 21050251308937 is a prime.

It is a super-2 number, since 2×213251292158812 (a number of 27 digits) contains 22 as substring.

Together with 21325129215883, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (21325129215883) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10662564607940 + 10662564607941.

It is an arithmetic number, because the mean of its divisors is an integer number (10662564607941).

Almost surely, 221325129215881 is an apocalyptic number.

It is an amenable number.

21325129215881 is a deficient number, since it is larger than the sum of its proper divisors (1).

21325129215881 is an equidigital number, since it uses as much as digits as its factorization.

21325129215881 is an evil number, because the sum of its binary digits is even.

The product of its digits is 691200, while the sum is 50.

The spelling of 21325129215881 in words is "twenty-one trillion, three hundred twenty-five billion, one hundred twenty-nine million, two hundred fifteen thousand, eight hundred eighty-one".