Base | Representation |
---|---|
bin | 1100011010011011110… |
… | …1000011011001000010 |
3 | 202101110001210222122010 |
4 | 3012212331003121002 |
5 | 11443221112420114 |
6 | 241545010153350 |
7 | 21256433443005 |
oct | 3064675033102 |
9 | 671401728563 |
10 | 213254420034 |
11 | 82493619147 |
12 | 353b6582856 |
13 | 17157320376 |
14 | a47055753c |
15 | 5831dcec59 |
hex | 31a6f43642 |
213254420034 has 32 divisors (see below), whose sum is σ = 426988929024. Its totient is φ = 71004839760.
The previous prime is 213254420023. The next prime is 213254420047. The reversal of 213254420034 is 430024452312.
213254420034 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×2132544200342 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 213254419983 and 213254420010.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 30588169 + ... + 30595139.
It is an arithmetic number, because the mean of its divisors is an integer number (13343404032).
Almost surely, 2213254420034 is an apocalyptic number.
213254420034 is an abundant number, since it is smaller than the sum of its proper divisors (213734508990).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
213254420034 is a wasteful number, since it uses less digits than its factorization.
213254420034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11982.
The product of its (nonzero) digits is 23040, while the sum is 30.
Adding to 213254420034 its reverse (430024452312), we get a palindrome (643278872346).
The spelling of 213254420034 in words is "two hundred thirteen billion, two hundred fifty-four million, four hundred twenty thousand, thirty-four".
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