Base | Representation |
---|---|
bin | 1100011010100111010… |
… | …0001010101111000111 |
3 | 202101120102010202121011 |
4 | 3012221310022233013 |
5 | 11443320410004341 |
6 | 241553443103051 |
7 | 21260555450545 |
oct | 3065164125707 |
9 | 671512122534 |
10 | 213302422471 |
11 | 82508725086 |
12 | 3540a671a87 |
13 | 17164259488 |
14 | a476a90d95 |
15 | 5836212b81 |
hex | 31a9d0abc7 |
213302422471 has 2 divisors, whose sum is σ = 213302422472. Its totient is φ = 213302422470.
The previous prime is 213302422409. The next prime is 213302422511. The reversal of 213302422471 is 174224203312.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 213302422471 - 211 = 213302420423 is a prime.
It is a super-3 number, since 3×2133024224713 (a number of 35 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (213302425471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106651211235 + 106651211236.
It is an arithmetic number, because the mean of its divisors is an integer number (106651211236).
Almost surely, 2213302422471 is an apocalyptic number.
213302422471 is a deficient number, since it is larger than the sum of its proper divisors (1).
213302422471 is an equidigital number, since it uses as much as digits as its factorization.
213302422471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 31.
Adding to 213302422471 its reverse (174224203312), we get a palindrome (387526625783).
The spelling of 213302422471 in words is "two hundred thirteen billion, three hundred two million, four hundred twenty-two thousand, four hundred seventy-one".
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