Base | Representation |
---|---|
bin | 110000011111111110001011… |
… | …100000010000011011111111 |
3 | 1000222020121002211001112211102 |
4 | 300133332023200100123333 |
5 | 210424230130113411312 |
6 | 2033354103413443315 |
7 | 62633440436561633 |
oct | 6037761340203377 |
9 | 1028217084045742 |
10 | 213303301310207 |
11 | 61a68470869589 |
12 | 1bb0b73804053b |
13 | 92035519c6694 |
14 | 3a95d133c8dc3 |
15 | 199d795b45ec2 |
hex | c1ff8b8106ff |
213303301310207 has 2 divisors, whose sum is σ = 213303301310208. Its totient is φ = 213303301310206.
The previous prime is 213303301310173. The next prime is 213303301310243. The reversal of 213303301310207 is 702013103303312.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 213303301310207 - 222 = 213303297115903 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 213303301310207.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (213303301310287) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106651650655103 + 106651650655104.
It is an arithmetic number, because the mean of its divisors is an integer number (106651650655104).
Almost surely, 2213303301310207 is an apocalyptic number.
213303301310207 is a deficient number, since it is larger than the sum of its proper divisors (1).
213303301310207 is an equidigital number, since it uses as much as digits as its factorization.
213303301310207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6804, while the sum is 29.
Adding to 213303301310207 its reverse (702013103303312), we get a palindrome (915316404613519).
The spelling of 213303301310207 in words is "two hundred thirteen trillion, three hundred three billion, three hundred one million, three hundred ten thousand, two hundred seven".
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