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2133124551281 is a prime number
BaseRepresentation
bin11111000010101000001…
…000011001001001110001
321112220222010011202011102
4133002220020121021301
5234422114341120111
64311535514054145
7310053546343253
oct37025010311161
97486863152142
102133124551281
117527202205a9
122a54b711a355
131261ca87bac9
147535ad03cd3
153a74a2d913b
hex1f0a8219271

2133124551281 has 2 divisors, whose sum is σ = 2133124551282. Its totient is φ = 2133124551280.

The previous prime is 2133124551211. The next prime is 2133124551289. The reversal of 2133124551281 is 1821554213312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1921716787600 + 211407763681 = 1386260^2 + 459791^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2133124551281 is a prime.

It is a super-2 number, since 2×21331245512812 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (2133124551289) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1066562275640 + 1066562275641.

It is an arithmetic number, because the mean of its divisors is an integer number (1066562275641).

Almost surely, 22133124551281 is an apocalyptic number.

It is an amenable number.

2133124551281 is a deficient number, since it is larger than the sum of its proper divisors (1).

2133124551281 is an equidigital number, since it uses as much as digits as its factorization.

2133124551281 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 57600, while the sum is 38.

Adding to 2133124551281 its reverse (1821554213312), we get a palindrome (3954678764593).

The spelling of 2133124551281 in words is "two trillion, one hundred thirty-three billion, one hundred twenty-four million, five hundred fifty-one thousand, two hundred eighty-one".