Base | Representation |
---|---|
bin | 11111000010101001001… |
… | …000101001101001001001 |
3 | 21112221000021212112211102 |
4 | 133002221020221221021 |
5 | 234422133144133131 |
6 | 4311541315111145 |
7 | 310054142461325 |
oct | 37025110515111 |
9 | 7487007775742 |
10 | 2133141396041 |
11 | 752729786297 |
12 | 2a55008a24b5 |
13 | 1262011c9016 |
14 | 7535d24a985 |
15 | 3a74ba151cb |
hex | 1f0a9229a49 |
2133141396041 has 2 divisors, whose sum is σ = 2133141396042. Its totient is φ = 2133141396040.
The previous prime is 2133141396013. The next prime is 2133141396077. The reversal of 2133141396041 is 1406931413312.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2116559425600 + 16581970441 = 1454840^2 + 128771^2 .
It is a cyclic number.
It is not a de Polignac number, because 2133141396041 - 226 = 2133074287177 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2133141395986 and 2133141396004.
It is not a weakly prime, because it can be changed into another prime (2133141396011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1066570698020 + 1066570698021.
It is an arithmetic number, because the mean of its divisors is an integer number (1066570698021).
Almost surely, 22133141396041 is an apocalyptic number.
It is an amenable number.
2133141396041 is a deficient number, since it is larger than the sum of its proper divisors (1).
2133141396041 is an equidigital number, since it uses as much as digits as its factorization.
2133141396041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 46656, while the sum is 38.
The spelling of 2133141396041 in words is "two trillion, one hundred thirty-three billion, one hundred forty-one million, three hundred ninety-six thousand, forty-one".
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