Base | Representation |
---|---|
bin | 11111000010101001010… |
… | …110111010111111011111 |
3 | 21112221000112220121121212 |
4 | 133002221112322333133 |
5 | 234422140123341434 |
6 | 4311541531215035 |
7 | 310054216332263 |
oct | 37025126727737 |
9 | 7487015817555 |
10 | 2133145137119 |
11 | 752730900a97 |
12 | 2a5501ba747b |
13 | 126201c08a89 |
14 | 7535d9420a3 |
15 | 3a74c0038ce |
hex | 1f0a95bafdf |
2133145137119 has 2 divisors, whose sum is σ = 2133145137120. Its totient is φ = 2133145137118.
The previous prime is 2133145137113. The next prime is 2133145137191. The reversal of 2133145137119 is 9117315413312.
Together with next prime (2133145137191) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2133145137119 - 228 = 2132876701663 is a prime.
It is a super-2 number, since 2×21331451371192 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2133145137113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1066572568559 + 1066572568560.
It is an arithmetic number, because the mean of its divisors is an integer number (1066572568560).
Almost surely, 22133145137119 is an apocalyptic number.
2133145137119 is a deficient number, since it is larger than the sum of its proper divisors (1).
2133145137119 is an equidigital number, since it uses as much as digits as its factorization.
2133145137119 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 68040, while the sum is 41.
The spelling of 2133145137119 in words is "two trillion, one hundred thirty-three billion, one hundred forty-five million, one hundred thirty-seven thousand, one hundred nineteen".
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